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by Riya
Fri Mar 09, 2018 1:45 pm
Forum: Ask Admission Consultants
Topic: A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 m
Replies: 0
Views: 1229

A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 m

Explanation: Let the original rate be R%. Then, new rate = (2R)%. Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s). 725 x R x 1 + 362.50 x 2R x 1 = 33.50 100 100 x 3 (2175 + 725) R = 33.50 x 100 x 3 (2175 + 725) R = 10050 (2900)R = 10050 R = 10050 = 3.46 290...
by Riya
Fri Mar 09, 2018 1:41 pm
Forum: Off Topic
Topic: A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and recei
Replies: 0
Views: 2260

A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and recei

Explanation:

Let the rate be R% p.a.

Then, 5000 x R x 2 + 3000 x R x 4 = 2200.
100 100
100R + 120R = 2200

R = 2200 = 10.
220
Rate = 10%.
by Riya
Fri Mar 09, 2018 12:52 pm
Forum: Off Topic
Topic: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14
Replies: 0
Views: 2080

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14

Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100
28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
by Riya
Fri Mar 09, 2018 12:52 pm
Forum: Off Topic
Topic: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14
Replies: 0
Views: 2168

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14

Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100
28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
by Riya
Fri Mar 09, 2018 12:31 pm
Forum: Share MANTRA Experience
Topic: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains
Replies: 0
Views: 1234

In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required percentage = 295 x 100 % = 1475 % = 70% (approximately).
420 21
by Riya
Fri Mar 09, 2018 12:25 pm
Forum: Share MANTRA Experience
Topic: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains
Replies: 0
Views: 1179

In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required percentage = 295 x 100 % = 1475 % = 70% (approximately).
420 21
by Riya
Fri Mar 09, 2018 12:16 pm
Forum: Critical Reasoning (CR)
Topic: Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his g
Replies: 0
Views: 1294

Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his g

Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.

Selling Price (S.P.) = Rs. 5800.

Gain = (S.P.) - (C.P.) = Rs.(5800 - 5500) = Rs. 300.

Gain % = 300 x 100 % = 5 5 %
5500 11
by Riya
Fri Mar 09, 2018 11:56 am
Forum: General Questions and Strategies
Topic: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is a
Replies: 0
Views: 1547

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is a

A's 2 day's work = 1 x 2 = 1 .
20 10
(A + B + C)'s 1 day's work = 1 + 1 + 1 = 6 = 1 .
20 30 60 60 10
Work done in 3 days = 1 + 1 = 1 .
10 10 5
Now, 1 work is done in 3 days.
5
Whole work will be done in (3 x 5) = 15 days