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Search found 19 matches
 by Jimit
 Fri Mar 09, 2018 5:35 pm
 Forum: Ask Admission Consultants
 Topic: A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6p.a for
 Replies: 0
 Views: 1234
A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6p.a for
Explanation:
Gain in 2 years
= Rs. 5000 x 25 x 2  5000 x 4 x 2
4 100 100
= Rs. (625  400)
= Rs. 225.
Gain in 1 year = Rs. 225 = Rs. 112.50
Gain in 2 years
= Rs. 5000 x 25 x 2  5000 x 4 x 2
4 100 100
= Rs. (625  400)
= Rs. 225.
Gain in 1 year = Rs. 225 = Rs. 112.50
 by Jimit
 Fri Mar 09, 2018 5:35 pm
 Forum: Ask Admission Consultants
 Topic: A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6p.a for
 Replies: 0
 Views: 1282
A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6p.a for
Explanation:
Gain in 2 years
= Rs. 5000 x 25 x 2  5000 x 4 x 2
4 100 100
= Rs. (625  400)
= Rs. 225.
Gain in 1 year = Rs. 225 = Rs. 112.50
Gain in 2 years
= Rs. 5000 x 25 x 2  5000 x 4 x 2
4 100 100
= Rs. (625  400)
= Rs. 225.
Gain in 1 year = Rs. 225 = Rs. 112.50
 by Jimit
 Fri Mar 09, 2018 5:04 pm
 Forum: Career Forum
 Topic: A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train runnin
 Replies: 0
 Views: 1061
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train runnin
Explanation:
Speed of train relative to jogger = (45  9) km/hr = 36 km/hr.
= 36 x 5 m/sec
18
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360 sec = 36 sec.
Speed of train relative to jogger = (45  9) km/hr = 36 km/hr.
= 36 x 5 m/sec
18
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360 sec = 36 sec.
 by Jimit
 Fri Mar 09, 2018 5:03 pm
 Forum: Career Forum
 Topic: A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train runnin
 Replies: 0
 Views: 1158
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train runnin
Explanation:
Speed of train relative to jogger = (45  9) km/hr = 36 km/hr.
= 36 x 5 m/sec
18
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360 sec = 36 sec.
Speed of train relative to jogger = (45  9) km/hr = 36 km/hr.
= 36 x 5 m/sec
18
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360 sec = 36 sec.
 by Jimit
 Fri Mar 09, 2018 4:50 pm
 Forum: Share MANTRA Experience
 Topic: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is
 Replies: 0
 Views: 1152
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is
Speed = 45 x 5 m/sec = 25 m/sec.
18 2
Time = 30 sec.
Let the length of bridge be x metres.
Then, 130 + x = 25
30 2
2(130 + x) = 750
x = 245 m
18 2
Time = 30 sec.
Let the length of bridge be x metres.
Then, 130 + x = 25
30 2
2(130 + x) = 750
x = 245 m
 by Jimit
 Fri Mar 09, 2018 4:47 pm
 Forum: Reading Comprehension
 Topic: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. Th
 Replies: 0
 Views: 1510
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. Th
Explanation:
Speed of the train relative to man = 125 m/sec
10
= 25 m/sec.
2
= 25 x 18 km/hr
2 5
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x  5) km/hr.
x  5 = 45 x = 50 km/hr.
Speed of the train relative to man = 125 m/sec
10
= 25 m/sec.
2
= 25 x 18 km/hr
2 5
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x  5) km/hr.
x  5 = 45 x = 50 km/hr.
 by Jimit
 Fri Mar 09, 2018 4:41 pm
 Forum: Data Sufficiency
 Topic: Two numbers A and B are such that the sum of 5% of A and 4% of B is twothird of the sum of 6% of A and 8% of B. Find th
 Replies: 0
 Views: 1237
Two numbers A and B are such that the sum of 5% of A and 4% of B is twothird of the sum of 6% of A and 8% of B. Find th
Explanation:
5% of A + 4% of B = 2 (6% of A + 8% of B)
3
5 A + 4 B = 2 6 A + 8 B
100 100 3 100 100
1 A + 1 B = 1 A + 4 B
20 25 25 75
1  1 A = 4  1 B
20 25 75 25
1 A = 1 B
100 75
A = 100 = 4 .
B 75 3
Required ratio = 4 : 3
5% of A + 4% of B = 2 (6% of A + 8% of B)
3
5 A + 4 B = 2 6 A + 8 B
100 100 3 100 100
1 A + 1 B = 1 A + 4 B
20 25 25 75
1  1 A = 4  1 B
20 25 75 25
1 A = 1 B
100 75
A = 100 = 4 .
B 75 3
Required ratio = 4 : 3
 by Jimit
 Fri Mar 09, 2018 4:40 pm
 Forum: Data Sufficiency
 Topic: Two numbers A and B are such that the sum of 5% of A and 4% of B is twothird of the sum of 6% of A and 8% of B. Find th
 Replies: 0
 Views: 1244
Two numbers A and B are such that the sum of 5% of A and 4% of B is twothird of the sum of 6% of A and 8% of B. Find th
Explanation:
5% of A + 4% of B = 2 (6% of A + 8% of B)
3
5 A + 4 B = 2 6 A + 8 B
100 100 3 100 100
1 A + 1 B = 1 A + 4 B
20 25 25 75
1  1 A = 4  1 B
20 25 75 25
1 A = 1 B
100 75
A = 100 = 4 .
B 75 3
Required ratio = 4 : 3
5% of A + 4% of B = 2 (6% of A + 8% of B)
3
5 A + 4 B = 2 6 A + 8 B
100 100 3 100 100
1 A + 1 B = 1 A + 4 B
20 25 25 75
1  1 A = 4  1 B
20 25 75 25
1 A = 1 B
100 75
A = 100 = 4 .
B 75 3
Required ratio = 4 : 3
 by Jimit
 Fri Mar 09, 2018 4:37 pm
 Forum: General Questions and Strategies
 Topic: If 20% of a = b, then b% of 20 is the same as:
 Replies: 0
 Views: 1195
If 20% of a = b, then b% of 20 is the same as:
Explanation:
20% of a = b 20 a = b.
100
b% of 20 = b x 20 = 20 a x 1 x 20 = 4 a = 4% of a.
20% of a = b 20 a = b.
100
b% of 20 = b x 20 = 20 a x 1 x 20 = 4 a = 4% of a.
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